Since the solution to the system of equation is 12 and -12, hence the equation has 2 solutions
<h3>Modulus functions</h3>
Modulus functions are functions that can either be positive or negative. Given the modulus function below;
|h| − 8 = 4
The modulus of h can both be negative and positive
If the modulus of h is positive then;
h - 8 = 4
Add 8 to both sides
h-8 + 8 = 4 + 8
h = 4 + 8
h = 12
If the value of h is negative
-h - 8 = 4
-h = 4 + 8
h =-12
Since the solution to the system of equation is 12 and -12, hence the equation has 2 solutions
Learn more on modulus function here: brainly.com/question/23450491
#SPJ1
The height of broken part of tree from ground is 5.569m.
Justification:
Let BD is a tree of height 12 m.
<u>Suppose it got bent at a point C and let the part CD take the position CA, meeting the ground at A</u>.
i.e., CD = AC = h m
<u>Broken part makes 60° angle from ground</u>
So, ∠BAC = 60°
<u>Now, height of remaining part of tree</u> = (12 – h)m.
In right angled ∆ABC,
sin 60° = BC/AC
⇒ √3/2 = (12 - h)/h
⇒ √3h = 2(12 – h)
⇒ √3h = 24 – 2h
⇒ √3h + 2h = 24
⇒ h(√3 + 2) = 24
⇒ h(1.732 + 2) = 24
⇒ h(3.732) = 24
⇒ h = 24/3.732 = 6.4308 m
<u>Hence, height of broken tree from ground</u>
⇒ BC = 12 – h
⇒ 12 – 6.4308 = 5.569m
<u>Hence, tree is broken 5.569 m from ground</u>.
<u>Note</u>: See attached picture.
Answer:
-9 + 7√5.
Step-by-step explanation:
(3 - √5)(2 + 3√5)
= 3(2 + 3√5) - √5(2 + 3√5))
= 6 + 9√5 - 2√5 - 15
= -9 + 7√5.
Answer:
It costs $42.43
Step-by-step explanation:
Lets explain how to solve the problem
- The cost of
kilogram of candy is $7.5
- We need to find the cost of
kilogram
We can use the ratio to find the answer
======= Dollar : Kilogram
======= 7.5 : 
======= c :
By using cross multiplication
∴ c ×
= 7.5 × 
∵
= 
∴
= 
∴ c ×
= 7.5 × 
∴ c ×
= 
Divide both sides by 
∴ c =
÷ 
Change the division sign to multiplication sign and reciprocal the
fraction after the division sign
∴ c =
×
∴ c =
= 42.43 dollars
∵ c represents the cost of
kg
∴ It costs $42.43
Answer:
m=6
x=6
Can i please have brainliest? I never get brainliest. :(