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3 years ago

I need the length of AC to the nearest 10th. If you can explain how you got it, that will be nice, but you don’t have too

Mathematics

2 answers:

Basile [38]3 years ago

8 0

Answer:

13.5

Step-by-step explanation:

Have a great day

Nezavi [6.7K]3 years ago

4 0

Answer:

13.5

Step-by-step explanation:

$\sin 64\degree = \frac{AC}{AB}\\\\AC = AB \sin 64\degree \\\\AC = 13.481910694\\\\AC \approx 13.5$

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Find the area of the trapezoid. Answer options: 60sqrt3, 52sqrt3, 44sqrt3 -24, 44sqrt3

antoniya [11.8K]

Answer:

= 52sqrt3

Step-by-step explanation:

Area of a trapezium is given by the formula;

1/2(a+b)h

Where a and b are the parallel sides and h is the perpendicular height.

a = 15 ft, b= 11 ft and h = 4√3

Therefore;

Area = 1/2 (15+11) 4√3

= 1/2 × 26 × 4√3

= 52√3 ft²

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2 years ago

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2/3x-2=5/6x

Naddik [55]

Answer:

x = - 12

Step-by-step explanation:

2 5

--- x - 2 = --- x

3 6

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---------------- = --------

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5 0

3 years ago

Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th

Sloan [31]

Answer: $3x^2y\sqrt[3]{y}\\\\$

Work Shown:

$\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\$

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

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2 years ago

What are the factors of 19

madam [21]

1 and 19, 19 is a prime number.

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3 years ago

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Alex73 [517]

Answer: log₂ $(\frac{h(n)}{6})$ + 1 = n