3 years ago

I need some help 3z2−6z3z2−6z for z=5

Mathematics

1 answer:

DiKsa [7]3 years ago

7 0

Um that would be -900

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10 < 0.25 ( x + 1 ) < 11

AURORKA [14]

10 <0.25 (x + 1) <11
We must solve two inequalities in this case.
Inequality 1:
10 <0.25 (x + 1)
10 / 0.25 <x + 1
40 <x + 1
40-1 <x
39 <x
Inequality 2:
0.25 (x + 1) <11
(x + 1) <11 / 0.25
(x + 1) <44
x <44-1
x <43
The final result is:
39 <x <43
Answer:
39 <x <43

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