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Harrizon [31]
3 years ago
7

What's the answer for this? Explain

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0
Exterior angle is equal to sum of interior opposite angles hence,

req. angle = 80 + 62 = 142
Svetach [21]3 years ago
4 0
Since it is a angle on a straight line, it is basicly as simple as:

180-38=142 degrees

As there is space for half a circle above a straight line. :)
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Triangle MRN is created when an equilateral triangle is folded in half.
Rus_ich [418]

The value of y based on the values given ib the equilateral triangle will be 4.

<h3>How to illustrate the triangle?</h3>

From the information given, MN is one of the sides of the equilateral triangle. Therefore, side MR will be:

= 1/2 × 8 = 4

In the above, it should be noted that MR was calculated since it's half of the value of MN which is 8.

Here, value of y based on the values given ib the equilateral triangle will be 4.

Learn more about triangles on:

brainly.com/question/17335144

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2 years ago
Unit price $12 for 150lb bag
makvit [3.9K]

Answer:

For $1 its 12.5lbs

Step-by-step explanation:

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3 years ago
60 pts for the person that answer and brainiest
vodomira [7]

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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te
alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = \frac{1}{4}.

Thus, the probability that the student does not receive version A = 1-\frac{1}{4} = \frac{3}{4}.

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}+\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}

= (\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5

= (\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]

= (\frac{3}{4^4})[1+\frac{1}{16}]

= (\frac{3}{256})[\frac{17}{16}]

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0
3 years ago
What is the expression for "the sum of 8 times a number and two"?
LiRa [457]

Answer:

8 N + 2

Step-by-step explanation:

==> 8 N + 2

-----------_________-------------

8 0
2 years ago
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