How many terms of the arithmetic series 3+9+15.... will add up to 19200?
1 answer:
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Answer:
The Greatest possible value of one of the integer is 140.
Step-by-step explanation:
Given: The average (arithmetic mean) of five different positive integers is 30.
To find: What is the greatest possible value of one of these integers?
Explanation: we are given that the arithmetic mean of five positive integer
is 30.
Let the five positive integers are A,B,C,D,E
The arithmetic mean :
=30.
On multiplying both side by 5.
A+B+C+D+E =150.
The least values of A ,B,C and D can be 1 ,2,3,4.
Then : 1 +2+3+4+E =150
On simplification 10+E =150
On subtraction both side by 10 we get
E = 140 .
Therefore, the Greatest possible value of one of the integer is 140.
Answer:
The blank is 3
Step-by-step explanation:
1 - Give the blank a variable
x = our blank
2 - Write it out
3 - Get the denominators equal
4 - Simplify
5 - Solve for the numerators
30+7x = 51
-30 -30
7x = 21
x = 3