Well as you can see it is F!
The new pool is 18.84 feet larger in circumference than the old one.
<u>Explanation:</u>
Given:
Circumference of the pool = 47.1 feet
Diameter of the new pool, d = 21 feet
radius, r = 21/2 feet
Circumference of the new pool = ?
We know:
Circumference = 2πr
where,
r is the radius
On substituting the value:
C = ![2 X 3.14 X \frac{21}{2}](https://tex.z-dn.net/?f=2%20X%203.14%20X%20%5Cfrac%7B21%7D%7B2%7D)
C = 65.94 feet
The difference in circumference of the two pools = 65.94 - 47.1 feet
= 18.84 feet
Therefore, the new pool is 18.84 feet larger in circumference than the old one.
Answer: the first one is 3y
Step-by-step explanation:
Go to the website mathpapa , type in the problem and it gives you the answer with steps