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3 years ago

6

Consider the graph and equation, y = 3x, that represent Alonso’s walking speed. What relationship is represented by this equatio

n and graph? What would the points (3, 9) and (5, 15) represent?

2 answers:

svlad2 [7]3 years ago

7 0

Answer:

The equation y = 3x represents a proportional relationship, where y represents distance in miles, and x represents time in hours. The point (3, 9) represents that Alonso walks 9 miles in 3 hours. The point (5, 15) represents that Alonso walks 15 miles in 5 hours.

Ira Lisetskai [31]3 years ago

4 0

Answer:

Step-by-step explanation:

The x value represents the time and y value represents the distance

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The vertices of ΔABC are A(−3,4), B(−2,4), and C(−5,2). If ΔABC is reflected across the line y=−2 to produce the image ΔA'B'C

Mumz [18]

The coordinates of vertex B' is $P'(x,y) = (-2, -8)$ .

<h3>How to calculate the coordinate of point by reflection</h3>

A point if reflected across the line $y = -2$ by means of the following formula:

$P'(x,y) = P(x,y)+2\cdot [(x_{P}, -2)-P(x,y)]$ (1)

Where:

$P(x,y)$ - Original point
$x_{P}$ - x-Coordinate of point P
$P'(x,y)$ - Resulting point

If we know that $P(x,y) = (-2,4)$ and $x_{P} = -2$ , then the coordinates of the vertex is:

$P'(x,y) = (-2, 4) + 2\cdot [(-2,-2)-(-2,4)]$

$P'(x,y) = (-2, 4) +2\cdot (0, -6)$

$P'(x,y) = (-2, 4) + (0,-12)$

$P'(x,y) = (-2, -8)$

The coordinates of vertex B' is $P'(x,y) = (-2, -8)$ . $\blacksquare$

To learn more on reflections, we kindly invite to check this verified question: brainly.com/question/1878272

3 0

3 years ago

Quadrilateral ABCD is a rectangle. If AG = -7j + 7 and DG = 5j + 43, find BD

Kaylis [27]

<em>BD</em> = 56

Step-by-step explanation:

Step 1: In rectangle, the diagonals are congruent and bisect each other.

So, <em>AC</em> = <em>BD</em>

⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>

⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>

⇒ 2<em>AG</em> = 2<em>GD</em>

⇒<em>AG</em> = <em>GD</em>

⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43

⇒–7<em>j</em> – 5<em>j</em> = 43 – 7

⇒–12<em>j</em> = 36

⇒<em>j</em> = –3

Step 2: <em>BD</em> = 2<em>DG</em>

<em>BD</em> = 2(5<em>j</em> + 43)

= 2(5 (–3) + 43)

= 2(–15 + 43)

= 2 × 28

= 56

Hence, <em>BD</em> = 56.

4 0

3 years ago

it takes three days for a snail to climb a wall. if a snail climds up the wall 2 in. in one day, then slids down 1 in. how tall

kkurt [141]

I believe the answer is 3 days.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C

MariettaO [177]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find out the gradient (Slope " m ") of line q ;

$\qquad \sf \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\qquad \sf \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}$

$\qquad \sf \dashrightarrow \:m = - 4$

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

$\qquad \sf \dashrightarrow \:y - 4 = m(x - 0)$

$\qquad \sf \dashrightarrow \:y = mx + 4$

Now, plug in the value of gradient ~

$\qquad \sf \dashrightarrow \:y = - 4x + 4$

here we can clearly observe that, the Area under the curve can easily be represented as :

$\qquad \sf \dashrightarrow \:y < - 4x + 4$

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0

2 years ago

Una avenida está siendo asfaltada por etapas. En la primera etapa se asfaltó la mitad; en la segunda, la quinta parte, y en la t

s344n2d4d5 [400]

Answer:

Sabemos que:

L es el largo de la avenida.

En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:

L - L/2 = L/2.

En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:

L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L

En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:

(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L

Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:

(2/40)*L = 200m

L = 200m*(40/2) = 4,000m

7 0

3 years ago