Well when two angles are supplementary they equal 180.
So if angle A is 80 degrees then that would mean that angle B equals 100 degrees.
Hope This Helped :)
-2^6-(6)^2= -100. Hope this helps have a great day. :)
EQUATION OF A CIRCLE = (x-h)² + (y-k)² =r²
Since the center of the cercle is in O, then h=5 & k=-2
(x-5)² + (y+2² =9
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
