$2.37 (the amount he spent on groceries) + <span>35¢ (or $0.35 he could spend on candy) = $2.72
Now you subtract this number from the five dollar bill to get the change.
5 - 2.72 = $2.28
His change was $2.28.
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Answer:
The answer is below
Step-by-step explanation:
The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

At 2 hours, the population is 62 cells, hence:

After another 2 hours (4 hours), the population is 1 million:

Put r = 4.844 in equation 1


You did not include the problem therefore i cannot help you with this but if you could message me the problem i’d be happy too