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4 years ago

What are the slope and the y-intercept of the linear function that is represented by the graph?

Mathematics

2 answers:

Alex4 years ago

6 0

Answer:

They-intercept of the linear function that is represented by the graph is (0,-2)

Step-by-step explanation:

it is where the line meets with the y-axis at a single point, in this case the point is (0,-2)

I hope that this helped

have a good day

Agata [3.3K]4 years ago

6 0

Answer:

Slope: 2/3; y-intercept: -2

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Use the following function rule to find f(3).

Vedmedyk [2.9K]

Answer:

f(3)= 33

Step-by-step explanation:

hello :

f(x) =8x+9

put x = 3 you have : f(3) =8(3)+9 = 24 + 9 =33

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3 years ago

5-10/8= 3 6/8 4 6/8 3 2/8 6 2/8

Oksi-84 [34.3K]

Answer:

3 6/8

Step-by-step explanation:

5 = 5

10/8 = 1 2/8

5 - 1 = 4

4 - 2/8 = 3 6/8

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3 years ago

Read 2 more answers

Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x > 0 [−4, 5]The f

quester [9]

Answer:

It is continuous since $\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)$

Step-by-step explanation:

We are given that the function is defined as follows $f(x) = 9-x, x\leq 0$ and $f(x) = 9+12x, x>0$ and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity) x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all $\mathbb{R}$ . So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

$\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)$ (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

$\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9$ . This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

$\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9$ . As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.