A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.
Let's look at your function.


is in the numerator. It is defined for every value of x. There is no problem there.

is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.
We set it equal to zero and solve the equation for x.



For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).
The answer is:
Answer: The answer is D. the data distribution is skewed to the right.
Step-by-step explanation:
Since in the picture it is shown that everything is more to the left but the tail is on the right side so it would be skewed right.
The sample space has 36 possible pairs from 1,1 1,2 1,3 up to 6,5 and 6,6
(a). Three pairs add to 4 1,3 2,2 and 3,1 so P(4) = 3/36 = 1/12
(b). 6 pairs add to 7 so P(7) = 6/36 = 1/6
(c) 15 pairs add to less than 7 so P(<7) = 15/36 = 5/12
Answer:
g[f(n)] = -8n+3
Step-by-step explanation:
Given,
g(n) = 2n + 5 , f(n) = -4n-1
Find g(f(n)),
Solutions,
g[f(n)] = g[-4n-1]
= 2(-4n-1) + 5
= -8n–2+5
g[f(n)] = -8n+3
Final Answer = g[f(n)] = -8n+3.