B not quiet sure but if anything try again : )
Using the binomial distribution, it is found that there is a:
a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.
b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.
c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.
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For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.
Binomial probability distribution

The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.96516 probability of a chipmunk living through the year, thus

Item a:
- Two is P(X = 2) when n = 2, thus:

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.
Item b:
- Six is P(X = 6) when n = 6, then:

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.
Item c:
- At least one not living is:

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.
A similar problem is given at brainly.com/question/24756209
Answer:
Therefore the only statement that is not true is b.)
Step-by-step explanation:
There employees are 6 secretaries, 5 consultants and 4 partners in the firm.
a.) The probability that a secretary wins in the first draw
= 
b.) The probability that a secretary wins a ticket on second draw. It has been given that a ticket was won on the first draw by a consultant.
p(secretary wins on second draw | consultant wins on first draw)
=
=
.
The probability that a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw =
is not true.
The probability that a secretary wins on the second draw = 
c.) The probability that a consultant wins on the first draw =

d.) The probability of two secretaries winning both tickets
= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)
= 
Therefore the only statement that is not true is b.)
9 a
------ = -----
a 5
a^2 = 45
a = 3<span>√5
</span>
4 b
------ = -----
b 5
b^2 = 20
b = 2√5
answer:
a = 3√5
b = 2√5
hope it helps
The answer would be:
A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin
See attached picture: