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Rama09 [41]
3 years ago
13

Find the midpoint of the segment with the following endpoints. (10,6) and (3,1)

Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0

Answer:

(6.5 , 3.5)

Step-by-step explanation:

Midpoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})\\

               =(\frac{10+3}{2},\frac{6+1}{2})\\\\=(\frac{13}{2},\frac{7}{2})\\\\=(6.5,3.5)

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Simplify by combining like terms: 9x - 3y -5x + 2y -x + 2
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Answer:

3x-y=-2

Step-by-step explanation:

9x-5x-x-3y+2y=-2

3x-y=-2

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3 years ago
The distance from a point on the number line to zero is known as:
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b. absolute value

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6 0
3 years ago
An observer in tower A sees a boat 1538 yd away at an angle of depression of 35°. To the nearest yard, how far is the boat away
Thepotemich [5.8K]
From my own solution, my answer is closest to D<span>. 1951 yd; 27°
</span><span>
The boat is 1951 yards away from the observer in tower B. The angle of depression to the boat from Tower B is 27</span>°.<span>

Pls. see my attachment. 

In it I divided the big triangle into two small right triangles. 
I solved for the common leg of the right triangles by using sin theta formula. sin </span>θ = opposite / hypotenuse
<span>
sin 35</span>° = opposite / 1538 yd
<span>sin 35</span>° * 1538 yd = opposite
<span>882.16 yd = opposite

From there, I used the Pythagorean theorem to solve for the missing side which is part of the 3,000 yd measure.

I got the measure of 1,259.86 yards. The remaining measure of 1,740.14 is the side of the other right triangle. 

Still using Pythagorean Theorem, I used the measurement of the known side of the 2nd right triangle to solve for its hypotenuse which was 1,950.97 or 1,951 yards.

With regards to the angle of depression, I used this formula:

tan(y) = opposite / adjacent
tan(y) = 1538 yd / 3000 yd
tan(y) = 0.513
y = 0.513/tan
y = 27.14</span>°<span>

</span>

8 0
3 years ago
What is the value of the expression below?<br><br> 0.72/0.36*2
Tanya [424]

Answer:

<h2>1</h2>

Step-by-step explanation:

0.72/0.36 x 2

0.72/0.72

1

I'm always happy to help :)

8 0
3 years ago
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