Answer:
The third quartile is 56.45
Step-by-step explanation:
The given parameters are;
The first quartile, Q₁ = 30.8
The median or second quartile, Q₂ = 48.5
The mean,
= 42.0
Coefficient of skewness = -0.38
The Bowley's coefficient of skewness (SK) is given as follows;

Plugging in the values, we have;

Which gives;
-0.38×(Q₃ - 30.8) = Q₃ + 30.8 - 2 × 48.5
11.704 - 0.38·Q₃ = Q₃ - 66.2
1.38·Q₃ = 11.704 + 66.2 = 77.904
Q₃ = 56.45
The third quartile = 56.45.
Answer:
The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept.
Step-by-step explanation:
The y-intercept of this line is the value of y at the point where the line crosses the y axis.
Answer:
See description.
Step-by-step explanation:
Any graph where the two lines intersect at (-3/2, 0) will be the correct graph.
Here is an attached example.
Answer:
A. 4(x - 4) + 2(3x² + 3x - 20)
C. (11x² + 7x - 55)-(5x² - 3x + 1)
F. (3x² + 5x - 28) + (3x² + 5x - 28)
Step-by-step explanation:
Given:
(3x-7)(2x+8)
= 6x² + 24x - 14x - 56
=6x² + 10x - 56
A. 4(x - 4) + 2(3x² + 3x - 20)
= 4x - 16 + 6x² + 6x - 40
= 6x² + 10x - 56
B. (3x² + 5x - 28) - (2x² + 4x + 28)
= 3x² + 5x - 28 - 2x² - 4x - 28
= x² + x - 56
C. (11x² + 7x - 55)-(5x² - 3x + 1)
= 11x² + 7x - 55 - 5x² + 3x - 1
= 6x² + 10x - 56
D. 4(x - 4) - 2(3x² + 3x - 20)
= 4x - 16 - 6x² - 6x + 40
= - 6x² - 2x + 24
E. (11x² + 7x - 55)-(5x² - 3x + 2)
= 11x² + 7x - 55 - 5x² + 3x - 2
= 11x² - 5x² + 7x + 3x - 55 - 2
= 6x² + 10x - 57
F. (3x² + 5x - 28) + (3x² + 5x - 28)
= 3x² + 5x - 28 + 3x² + 5x - 28
= 6x² + 10x - 56
<span>s = -16t^2 + 88t + 5
Time to reach the maximum height = 88/32
= 2.75 seconds
Maximum height = -16(2.75)^2 + 88 (2.75) +5
= -121 + 242 + 5
= 126 Feet
Range: 5<y<44</span>