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nlexa [21]
3 years ago
5

What is 85.92 divided by 4

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

correct is it Because CorrectA.

cluponka [151]3 years ago
6 0

Answer:

The answer of your question : 85.92 divided by 4 is equal to (21.48)

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The owner of a large restaurant is considering a new “no tipping” policy and wants to survey a sample of employees. The policy w
Stolb23 [73]

A) The strata to be used in this survey by the employer is; <em><u>Type of Staff</u></em>

B) <em>Stratified Random Sampling</em> will be preferred because the opinions of <em><u>the staffs on the tipping policy</u></em> may be the same within each type but differ across the different <u><em>types of staffs.</em></u>

  • A stratified random sampling is a type of sampling that divides a population into groups known as strata.

Now, from the question, we see that after adding a 20% to the cost of food and beverages, that the additional revenue will be distributed equally among the kitchen and server staffs.

This means the strata here will be the type of staff because the opinions of the staffs on the tipping policy may be the within each type but differ across both types of staffs.

Read more at; brainly.com/question/1954758

7 0
2 years ago
25000ft to gal help me please
Alex787 [66]
25000ft=187012.99gal
4 0
3 years ago
Rearrange the following numbers in order from least to greatest.
inysia [295]

Answer:

-25, -14, -10, -9, -8, -7, 0, 2

Step-by-step explanation:

You do thing and it work

5 0
3 years ago
Read 2 more answers
Divide the number 720 into the following Ratios<br><br>2:1:3<br><br>5:4​
solmaris [256]

Answer:

Ratio 1 = a(240

=b)120

=c)360

Ratio 2=a)400

=b)320

Step-by-step explanation:

On both of the ratios you first add them then divide one by one like this for example 2+1+3= 6

then 2/6 ÷720 = 120 ×2 =240 then you do this to the other numbers as well.

6 0
2 years ago
Read 2 more answers
Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se
defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

p_{1}(t) = 1, p_{2}(t)= t^{2} and p_{3}(t) = 3 + 3\cdot t:

\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0

\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0

(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0

The following system of linear equations is obtained:

\alpha_{1} + 3\cdot \alpha_{3} = 0

\alpha_{2} = 0

\alpha_{3} = 0

Whose solution is \alpha_{1} = \alpha_{2} = \alpha_{3} = 0, which means that the set of vectors is linearly independent.

p_{1}(t) = t, p_{2}(t) = t^{2} and p_{3}(t) = 2\cdot t + 3\cdot t^{2}

\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0

\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0

(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0

The following system of linear equations is obtained:

\alpha_{1}+2\cdot \alpha_{3} = 0

\alpha_{2}+3\cdot \alpha_{3} = 0

Since the number of variables is greater than the number of equations, let suppose that \alpha_{3} = k, where k\in\mathbb{R}. Then, the following relationships are consequently found:

\alpha_{1} = -2\cdot \alpha_{3}

\alpha_{1} = -2\cdot k

\alpha_{2}= -2\cdot \alpha_{3}

\alpha_{2} = -3\cdot k

It is evident that \alpha_{1} and \alpha_{2} are multiples of \alpha_{3}, which means that the set of vector are linearly dependent.

p_{1}(t) = 1, p_{2}(t)=t^{2} and p_{3}(t) = 3+3\cdot t +t^{2}

\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0

\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0

(\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0

The following system of linear equations is obtained:

\alpha_{1}+3\cdot \alpha_{3} = 0

\alpha_{2} + \alpha_{3} = 0

3\cdot \alpha_{3} = 0

Whose solution is \alpha_{1} = \alpha_{2} = \alpha_{3} = 0, which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.

4 0
3 years ago
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