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3 years ago

Which of the following is the midpoint formula?

Mathematics

1 answer:

Alika [10]3 years ago

5 0

B is the right answer

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3x+9=1x what’s the slope and intercept form

tresset_1 [31]

Answer:

this equation cannot be written in slope-intercept form

Step-by-step explanation:

The given equation is equivalent to ...

2x +9 = 0 . . . . . subtract 1x

x + 4.5 = 0 . . . . divide by 2

x = -4.5 . . . . . . . the equation of a vertical line.

It has no y-intercept and its slope is undefined.

5 0

3 years ago

Use the formula d=rt Find t for r = 48.3 m/h and d = 545.79 m.

djyliett [7]

D = 545.79
r = 48.3

Plug in numbers to corresponding variables

545.79 = t(48.3)

Isolate the t, divide 48.3 from both sides

(545.79)/48.3 = 48.3t/48.3

t = 545.79/48.3
t = 11.3

t = A) 11.3 h

hope this helps

8 0

3 years ago

Isaac's hair was 12 centimeters long after his last haircut, and it grows 8 centimeters every year. Isaac last got his hair cut

SOVA2 [1]

Answer:

Step-by-step explanation:

1.) 8 x 8 =64

2.) 12 + 64 =76

8 0

3 years ago

Read 2 more answers

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago

3^x.2x = 3^x + 2x-1

sattari [20]

Answer:

x=0

Step-by-step explanation:

answer x=0

3 0

3 years ago