Answer:
The proportion of scores reported as 1600 is 0.0032
Step-by-step explanation:
Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).
In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)
The values of the cummulative distribution function of the standard Normal random variable, lets denote it 
are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600
Hence, the proportion of scores reported as 1600 is 0.0032.
Answer:
8r^4
Step-by-step explanation:
√(64r^8) = √((8r^4)^2) = 8r^4
_____
You can make use of either or both of these rules of exponents:
(a^b)^c = a^(b·c) . . . . . used above
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Using the second rule, you can write the expression as ...
$860/$11,565 * 100% ≈ 7.4% . . . . matches selection B
Answer:
n/4 - 3
Step-by-step explanation:
Let's "break" the statement in simpler parts:
First, we start with a number n.
Now, we need to find one fourth of that number, that is:
(1/4)*n = n/4
And finally, we need to subtract 3 from that, then we get:
n/4 - 3
So the statement:
"Emily is thinking of a number she calls it n then she finds 1 fourth of it and subtracts 3"
Can be written as:
n/4 - 3
The answer is 44. You divide 88 by 2 which is half, so it's 44! Hope this helps!! ;))
