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motikmotik
3 years ago
6

13) zy + 4y; use y=5, and z=2

Mathematics
2 answers:
AysviL [449]3 years ago
6 0

Answer:

30

Step-by-step explanation:

Substitute the given values for y and z into the expression

zy + 4y = (2 × 5) + (4 × 5) = 10 + 20 = 30

Iteru [2.4K]3 years ago
3 0

Answer:30

Step-by-step explanation:2x5+4x5=30

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Construct an equilateral triangle of side 7cm and construct circumcircle.
zalisa [80]

Answer:

To do this, all you need is to draw triangle with each side being 7 cm, and a circle that intersects all three of its corners.

Step-by-step explanation:

  1. With a ruler and a pencil, draw a 7cm line.
  2. With a compass set to a radius of 7cm draw an arc centered around the right end of the line.
  3. With the same compass, still at 7cm, draw an arc centered around the left end of the line.
  4. These two arcs will intersect on either side of the line (you only need one side, so you only need a small arc in the right place, roughly where you think the third point if the triangle is.
  5. Where those arcs intersect is the third point on your triangle.  Mark that, and then trace two lines from that point to either end of the line segment you started with.

<em>You now have an equilateral triangle with 7cm sides.  Next you need to draw the circle</em>

  1. Measure the halfway point on two of your three lines.
  2. Draw a line from that each of those halfway points to the opposite corner. The new lines you're drawing will be perpendicular to the edge your measuring against.
  3. You have now drawn two line segments, and they intersect in the center of the circle.  Now take your compass and set its radius to the distance from that center point to one of the three corner points.
  4. Centered on that middle point, trace a circle with the selected radius.

And you're done!

6 0
2 years ago
How to find cos2theta
SSSSS [86.1K]
You can use the sum and difference identities which for cosine is cos(a+b)= cosacosb-sinasinb
5 0
3 years ago
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Ation in an Application Problem
Greeley [361]
Less than $3 because 25/7/2
6 0
3 years ago
HELPP 35 POINTS!!!!! Point Q is the center of Circle Q in the diagram below. The measure of angle XAY is 72° (m∠XAY = 72°). Sinc
Paladinen [302]

Answer:

Se explanation

Step-by-step explanation:

The diagram shows the circle with center Q. In this circle, angle XAY is inscribed angle subtended on the arc XY. Angle XQY is the central angle subtended on the same arc XY.

The inscribed angle theorem states that an angle inscribed in a circle is half of the central angle that subtends the same arc on the circle. Therefore,

m\angle XBY=2m\angle XAY=2\cdot 72^{\circ}=144^{\circ}

The measure of the intercepted arc XY is the measure of the central angle XQY and is equal to 144°.

All angles that have the same endpoints X and Y and vertex lying in the middle of the quadrilateral XAYQ have measures satisfying the condition

72^{\circ}

because angle XAY is the smallest possible angle subtended on the arc XY in the circle and angle XQY is the largest possible angle in the circle subtended on the arc XY.

6 0
3 years ago
Can anyone help me please
Lena [83]

Answer:

$55.24

Step-by-step explanation:

Add $32.78 + $27.24 + $5.22

= 65.24

Subtract 10

= $55.24

4 0
3 years ago
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