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zysi [14]
3 years ago
15

determine the most appropriate hypothesis test to use for the following scenario: the august 2008 edition of academy of manageme

nt journal featured an investigation of the performance and tiing of corporate acquisitions. the investigations discovered that in random sample of 2778 firms, 748 annouced one or more acquisitions during the year 2000. does the sample provide suffcient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is less than 30%
Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

Since the calculated z =-3.5357 falls in the critical region z ≥ 1.645 we reject H0 and conclude that the sample provides sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is ≥ 30%

Step-by-step explanation:

<u><em>Testing  hypothesis about a population proportion when sample size is large.</em></u>

If the sample size is large then the variable

z= p^-p / sqrt [pq/n]

is approximately standard normal.

Formulate the hypotheses as

H0 : p < 30%   against the claim Ha: p ≥ 30%

Choose the significance level ∝= 0.05

the critical region is z ≥ 1.645 because the alternative hypothesis is stated on a greater  than or equal to basis.

Computing

Z= 748-(2778*0.3)/ √2778*30/100*70/100

z= 748-833.4/√583.38

z= -85.4/24.153

z=-3.5357

Since the calculated z =-3.5357 falls in the critical region z ≥ 1.645 we reject H0 and conclude that the sample provides sufficient evidence to indicate that the true percentage of all firms that announced one or more acquisitions during the year 2000 is ≥ 30%

The p- value is 0.0002

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<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

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10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

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5 0
3 years ago
Find 4 consecutive even integers whose sum is 156?
snow_tiger [21]
X+(x+1)+(x+2)+(x+3)=156
4x+6=156
4x=150
x=37.5 (not an integer)
If x=37 you get 37+38+39+40=154 and if x=38 you get 38+39+40+41=158[/tex]
8 0
3 years ago
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Answer:

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2 years ago
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Step-by-step explanation:

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4 0
3 years ago
ASAP what is the value of k?<br> -3(k+7) - 5k+4=23
Maru [420]

Answer:

k=−5

Step-by-step explanation:

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Step 2: Add 17 to both sides.

−8k−17+17=23+17

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Step 3: Divide both sides by -8.

−8k

−8

=

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Answer:

k=−5

 

6 0
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