Answer:
The given point A (6,13) lies on the equation. True
The given point B(21,33) lies on the equation. True
The given point C (99, 137) lies on the equation. True
Step-by-step explanation:
Here, the given equation is : 
Now,check the given equation for the given points.
1) A (6,13)
Substitute x = 6 in the given equation
⇒ y= 13
Hence, the given point A (6,13) lies on the equation.
2) B (21,33)
Substitute x = 21 in the given equation
⇒ y = 33
Hence, the given point B(21,33) lies on the equation.
3) C (99, 137)
Substitute x = 99 in the given equation
⇒ y = 137
Hence, the given point C (99, 137) lies on the equation.
Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:
D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square) two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0
Answer is:
<span>A two irrational solutions </span>
Answer:
$200
Step-by-step explanation:
Amanda Beverly
9 : 3
difference between Amanda and Beverly = 9 - 3 = 6 portions.
∴ value of 6 portions = $60
value of 1 portion = $ 60 / 6
= $10
Total no. of portions = 8 + 9 + 3 = 20
Total sum of money to be shared = value of 1 portion x Total no. of portions
= $10 x 20
= <u>$200</u>
Answer:
a. 
.
b. 
Step-by-step explanation:
By the definition, the expected value of a random variable X with probability mass function p is given by 
where the sum runs over all the posible values of X. Given a function g, the random variable Y=g(X) is defined. Note that the function g induces a probability mass function P' given by P'(Y=k) = P(X=g^{-1}(k)) when the function g is bijective.
a. Note that for 1/3ln(2)+1/6ln(5) by choosing the function g(x) = ln(x) the expression coincides with E(g(x)), because if Y = g(x) then E(Y) = P'(Y=1)*ln(1)+P'(Y=2)*ln(2)+P'(Y=5)*ln(5) = P(X=1)*ln(1)+P(X=2)*ln(2)+P(X=5)*ln(5).
b. On the same fashion, the function g(x) = xe^{xt} fullfills the expression of E[g(X)]
1pound is 800/560......which is 80/56-->10/7
so 1 pound is 10/7 dollars....
because you don't say for one dollar it is this many pounds.
also for unit rate i divide by 560 on both sides to get one pound on one side and then how many dollars on the other
