Question

Employees at the ACME paper bag corporation have two fast food restaurant chains located next to the corporate parking lot: Carl's Jr. and Wendy's. Due to time restrictions the ACME employees eat their lunches either at Carl's Jr. or Wendy's and nowhere else. If today an employee eats lunch at Wendy's, then tomorrow the probability they'll eat lunch at Wendy's is 10% otherwise they'll eat lunch at Carl's Jr. If today an employee eats lunch at Carl's Jr., then tomorrow the probability they'll eat lunch at Carl's Jr. is 40% otherwise they'll eat lunch at Wendy's. If on Monday an employee eats lunch at Carl's Jr. what is the probability they'll eat lunch at Carl's Jr. Wednesday?

Answer 1

Answer:

0.7 = 70% probability they'll eat lunch at Carl's Jr. Wednesday.

Step-by-step explanation:

We have that:

Carl's Jr on Monday.

On Tuesday:

40% probability of Carl's Junior.

100 - 40 = 60% probability of Wendy's.

On Wednesday:

If on Tuesday it was on Carl's Junior, 40% probability of Carl's Junior on Wednesday.

In on Tuesday it was on Wendy's, 100 - 10 = 90% probability of Carl's Junior on Wednesday.

What is the probability they'll eat lunch at Carl's Jr. Wednesday?

$p = 0.4*0.4 + 0.6*0.9 = 0.7$

0.7 = 70% probability they'll eat lunch at Carl's Jr. Wednesday.