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Effectus [21]
3 years ago
10

Josh ran 84.6 miles in June. In July he ran 0.55 times this distance due to an injury. How many more miles did he run in June th

an in July?
Mathematics
2 answers:
lidiya [134]3 years ago
7 0

Answer:

The answer is 84.05!

Do 84.60 - 0.55 to get 84.05!

Hope this helped!

Irina-Kira [14]3 years ago
5 0

I did 0.80-0.25=0.55

so I figured that is what she had left so I know took the total 0.80-0.55 and got0.25 which is B.

My friend said the correct answer was A.

Don't worry I just did this problem!

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kipiarov [429]

Answer:

Step-by-step explanation:

Let's FOIL this out and get it into standard quadratic format:

h(t)=-4.9t^2+490. The lack of a linear term in the middle means therewas no upwards velocity, consistent with the object being dropped straight down as opposed to thrown up in the air tand then falling in a parabolic path. The -4.9t² represents the acceleration due to gravity, and the 490 represents the height from which the object was dropped. The constant in a quadratic that is modeling parabolic motion always represents the height from which the object was dropped (or launched). That's how you know.

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Suppose that $9500 is placed in an account that pays 8% interest compounded each year.
Blababa [14]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$9500\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{each year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}


\bf A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 1}\implies A=9500(1.08)\implies \boxed{A=10260} \\\\\\ \stackrel{\textit{after 2 years, t = 2}}{A=9500\left(1+\frac{0.08}{1}\right)^{1\cdot 2}}\implies A=9500(1.08)^2\implies \boxed{A=11080.8}

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Answer:

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Hello :) the answer to your question would be 5. There are 5 bricks in each bag. 35/8
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