The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Answer:
9
Step-by-step explanation:
The mode is the number that occurs most often. The number nine occurs 4 times.
Change in level is given by :
C = increase in level - decrease in level.
Now,
Decrease in level in March is 2 1/4 = 9/4 inches.
Increase in level in April is 1 5/8 = 13/8 inches.
Putting value of these in above equation, we get :
C = 13/8 - 9/4
C = 13/8 - 18/8
C = -5/8 inches
Therefore, the overall level after April will decrease by 5/8 inches.
Hence, option 4. is correct.
20 + 40x = 260
40x = 260 - 20
40x = 240
x = 240/40
x = 6 fulltime employees needed
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