HELP!! Please solve these showing work thank you!!!!
1 answer:
1) g=6x divide both sides by 6 -> g/6=x
3)z=m-x subtract both sides by m -> z-m=-x flip the positive negative on each side->-z+m=x or m-z=x
5)u=x-k add k to each side -> u+k=x
7)u=k/a multiply each side by a -> ua=k divide each side by u-> a=k/u
9) 12am=4 divide each side by 12-> am=4/12=1/3 divide each side by m->
a=
10)-3x+2c=-3 subtract 2c from ech side ->-3x=-3-2c divide each side by -3 ->x=-3-2c/-3 = 2c+3/3
11)am=n+p divide both sides by m -> a=n+p/m
16)g=x-c+y subtract both sides by y -> g-y=x-c add both sides with c -> g-y+c=x
i hope these are correct
You might be interested in
Answer:
c = 15d + 30
Step-by-step explanation:
Hey there!
This can be represented by an equation of a line, where the number of days is our x-values(d), and the price is our y-values(c).
The price for one day ($45) and the price for 4 days($90) are specific points on that line.
The points are (1, 45) and (4, 90).
We can first find the slope of the line:
- As the price rises 45, the days increase by 3
- Slope = rise/run
- Slope = 45/3
- Slope = 15
Now we can find the base price, by plugging the slope and a point into the equation y = mx + b.
Solve for b:
- y = mx + b
- 45 = 15(1) + b
- 45 = 15 + b
- 30 = b
The base price (b) is 30.
The equation is