All categories

3 years ago

A small fly weighs approximately 2.2 * 10^-3 gram and an average sized gnat weighs approximately 9*10^-4

Mathematics

2 answers:

antoniya [11.8K]3 years ago

6 0

Answer:

0.0068

Step-by-step explanation:

I'm taking this right now hope this helps

WARRIOR [948]3 years ago

3 0

Answer:

What is the question???

Step-by-step explanation:

You might be interested in

Which of the following points are correct for the equation (multiple answers)

mezya [45]

Answer:

1,5 is your answer

Y=5 and X=1

Insert it in the equation

5=3(1)+2

5=3+2

5=5

Hence proved!

5 0

4 years ago

PLEASE PLEASE PLEASEEEEEE!!!! fill it out and insert it into your answer

kaheart [24]

Answer:

Step-by-step explanation:

The line will not pass through the origin.

Instead, the graph will cross the y-axis at a point known as the y-intercept.

3 0

3 years ago

Which lines are perpendicular to the line y – 1 = One-third(x+2)

Valentin [98]

Answer:

$y-1=-3(x+2)$

Step-by-step explanation:

The equation of the given line:

$y-1=\frac{1}{3}(x+2)$

This equation is in the form $y-y_{1}=m(x-x_{1})$ . Therefore, 1/3 is the slope.

To find a perpendicular line, take the opposite reciprocal of the slope (-1/old slope). Therefore, the slope of the perpendicular line is -3.

The equation of the perpendicular line: $y-1=-3(x+2)$

4 0

3 years ago

A study of women’s weights found that a randomly selected sample of 234 women had a mean weight of 157.3 lb. Assuming that the p

Scilla [17]

Answer:

$157.3-1.96\frac{15.6}{\sqrt{234}}=155.301$

$157.3+1.96\frac{15.6}{\sqrt{234}}=159.299$

So on this case the 95% confidence interval would be given by (155.301;159.299)

And the best option would be:

B. (155.3, 159,3)

Step-by-step explanation:

Information given

$\bar X=157.3$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma =15.6$ represent the population standard deviation

n=234 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level is is 0.95 or 95%, the significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value for this case would be $z_{\alpha/2}=1.96$

And replacing we got:

$157.3-1.96\frac{15.6}{\sqrt{234}}=155.301$

$157.3+1.96\frac{15.6}{\sqrt{234}}=159.299$

So on this case the 95% confidence interval would be given by (155.301;159.299)

And the best option would be:

B. (155.3, 159,3)

5 0

4 years ago

PLEASE HELP!!

Nitella [24]

Answer:

Step-by-step explanation:

7 0

3 years ago