First, do 5 = 12 = 17.
Look at the numbers you have.
What numbers can make 17?
You basically add ().
You add the () between 2 x 6 (2x6) to show that you do that first.
Then, once you get the answer for that, add 5.
5+(2x6) = 17.

I hope this helps! :D

5 0

3 years ago

six ants simultaneously stand on the six vertices of a regular octahedron, with each ant at a different vertex. simultaneously a

Thepotemich [5.8K]

The probability that no two ants will reach the same vertex is 5/256.

Plane, point B and attention. Ants that move to D can come from either E or C. Ants moving to E can come from either B or D of points A and F of the octahedron. Therefore, there are 2 degrees of freedom to decide which ants move to D, 2 degrees of freedom to decide which ants move to E, and 2 degrees of freedom to decide which ants move to A.

So there are 2× 2× 2=8 ways an ant can move to different points.

There are 8 ways for ants to move to different points.

Points B, there are a total of 8 + 4 + 8 = 16 ways Ant can move to her different points. Aligned the square so that point B is defined as point where the ant moved from point A.

An ant can actually move from point A to 4 different points, so there are a total of 4×20=80 ways an ant can move to different points.

Each ant acts independently and has 4 different points to choose from.

So each ant has a 1/4 chance of moving to the desired location. Since he has 6 ants, the probability of appearance is

= 1/4096

So, the desired answer is 80/4096

= 5/256

To learn more about probability, visit:

brainly.com/question/13024117

#SPJ4

3 0

2 years ago