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yanalaym [24]
3 years ago
7

Find the missing side length in the right triangle. ​

Mathematics
2 answers:
sergejj [24]3 years ago
8 0

Answer:

12.7

Step-by-step explanation:

Readme [11.4K]3 years ago
6 0

I’m pretty sure the answer is 6, please correct me if I am wrong.

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Please help with math it’s easy!! explanation needed!
Diano4ka-milaya [45]

Answer:

There is 1 solution

Step-by-step explanation:

y = -3 (x+1) ^2

Using the zero product property

0 =  -3 (x+1) ^2

Divide by -3

0 =   (x+1) ^2

Take the square root of each side

sqrt(0) =  sqrt( (x+1) ^2)

0 = x+1

Subtract 1 from each side

-1 =x

There is 1 solution

6 0
3 years ago
Read 2 more answers
Use the rules of equations and inverse operations to solve the equation. -x^3=216
Leni [432]
The answer for this problem is B:-6

8 0
4 years ago
Read 2 more answers
Hi there! please help with this.
USPshnik [31]

Answer:

Step-by-step explanation:

I dont know wish I could help, srry.

5 0
3 years ago
Show how to solve -5y+8=-3y+10
marta [7]
-5y+8=-3y+10
-5y+3y=10-8
-2y=2
-2y/-2=2/-2
y=-1

I grouped the alike variable to one side, and the number to the other side, added and subtracted it, divided both sides by -2, and got -1
8 0
3 years ago
Read 2 more answers
What are the values of a and b​
makvit [3.9K]

Answer:

\large\boxed{B.\ a=8,\ b=4\sqrt5}

Step-by-step explanation:

We have three similar triangles:

\triangle ABC\sim\triangle DBA\sim\triangle DAC

therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{BD}{AD}

We have AD = a, CD = 16 and BD = 4. Substitute:

\dfrac{a}{16}=\dfrac{4}{a}              <em>cross multiply</em>

(a)(a)=(16)(4)\\\\a^2=64\to a=\sqrt{64}\\\\a=8

and other proportion:

\dfrac{AB}{BC}=\dfrac{BD}{AB}

We have AB = b, BC = 16 + 4 = 20 and BD = 4. Substitute:

\dfrac{b}{20}=\dfrac{4}{b}             <em>cross multiply</em>

(b)(b)=(20)(4)\\\\b^2=80\to b=\sqrt{80}\\\\b=\sqrt{16\cdot5}\\\\b=\sqrt{16}\cdot\sqrt{5}\\\\b=4\sqrt{5}

3 0
3 years ago
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