Answer:
<h2>x = 1</h2>
Step-by-step explanation:
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
1/2 + 9/20 = 19/20
1/20 + 1/10 = 3/20
1/8 + 11/16 = 13/16
2/9 + 5/9 = 7/9
3/20 + 3/4 = 18/20 = 9/10
7/17 + 1/17 = 8/17
F = (-3,3)
scale factor of 10
-3 * 10 = -30
3 * 10 = 30
answer : (-30,30)
35714286/1000000000, simplified is <span>17857143/500000000.</span>
