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3 years ago

14

Write the given linear system without the use of matrices. Assume X = x y z . X' = 7 6 −9 5 1 1 0 −3 4 X + 0 3 1 e6t − 8 0 4 e−3

t

1 answer:

lapo4ka [179]3 years ago

8 0

Answer:

X= 3

Step-by-step explanation:

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a company just announced that it has made a profit £4 million. It is going to give 2/7 of this to charity. How much will it give

Arte-miy333 [17]

Answer:

Approximately- 1142857 pounds.

Step-by-step explanation:

Just multiply 4M (6 zeros), with proportion:

(4*10^6)*(2/7)= the answer that i've gave you

7 0

2 years ago

Help pls<br> ty in advance

svetoff [14.1K]

$\bold{\huge{\underline{ Solution\: 2 }}}$

The name of the circle is <u>IJKL</u>
The name of central Angle
$\sf{\underline{= {\angle} IHJ }}$
The name of the secant = <u>KL</u>

${\bigstar}$ Circle :- It is a round figures, which has no end points.

${\bigstar}$ Central angle :- It the angle ,which lie in the middle of the circle.

Here, H is the mid point of the circle .So, Angle IHJ is the central angle.

${\bigstar}$ Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .

Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

$\bold{\huge{\underline{ Solution\: 3 }}}$

Semicircle = FGH and FIH
Minor Arc :- FG or GH
Major Arc :- FHG or GFH

${\bigstar}$ Semicircle :- Semicircle is nothing but the half of the circle.

<u>Here</u><u>, </u><u>In </u><u>second </u><u>diagram </u>

FGH and FIH are acting as two semicircles which simulatineously forming one circle.

${\bigstar}$ Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.

<u>Here</u><u>, </u>

FG or GH are the minor arc of the given circle.

${\bigstar}$ Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.

<u>Here</u><u>, </u>

FHG or GFH is the major arc as it is larger than the semicircle of the given circle .

7 0

2 years ago

Plot the points A(−2,−3) , B(−3,0) , C(3,2) , and D(4,−1) . What type of quadrilateral is ABCD ? Justify your answer using mid-p

Alika [10]

Obtuse quadrilaateral. midpoint(-1,3) with slooe 1/2
distance 2

6 0

3 years ago

Please help ASAP!

Lana71 [14]

1)x+1) has positive slope, it is only A or B
2) For f(x)=4 we have x≥1, so this graph should begin with black dot.
3)So answer is B
Blue dot should be empty.
Orange dot should be black.

8 0

4 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

3 years ago