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Dmitriy789 [7]
2 years ago
5

QUESTION 1 Calculate the volume 5 cm 6 cm 8 cm

Mathematics
2 answers:
bixtya [17]2 years ago
7 0

Answer:

5×6×8=240 is the answer. I hope it helps you.

Masteriza [31]2 years ago
3 0

Step-by-step explanation:

Volume = l * b * h

volume \:  = 5 \times 6 \times 8 \\  = 240 \: cm^{3}

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What is the slope of the line that passes through the points ( 10 , − 6 ) (10,−6) and ( 8 , − 16 ) ? (8,−16)?
GaryK [48]

Answer:

5

Step-by-step explanation:

-16-(6)

over

8-10

slope= -10/-2

simplify:

5/1=5

4 0
3 years ago
Help me I will give extra points
dlinn [17]

Answer: g(x) = -4x + 5

Please mark me brainliest instead of points

3 0
3 years ago
The ratio of the surface areas of two similar solids is 4:49. What is the ratio of a volumes?
Fynjy0 [20]

Answer: 8/343

Step-by-Step:

If two similar solids have a scale factor of a:b then,

The ratio of their surface areas (2D) is- a^2:b^2

The ratio of their volume (3D) is- a^3:b^3

First you want to square root the scale factor numbers to find the original value. Then you cube the original numbers to find the answer.

6 0
3 years ago
Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?
bagirrra123 [75]
\bf \begin{array}{clclll}
-6&+&6\sqrt{3}\ i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\
-------------------------------\\\\

\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}
\\\\\\
r=12\leftarrow 
\\\\\\
\theta =tan^{-1}\left( \frac{6\sqrt{3}}{-6} \right)\implies \theta =tan^{-1}\left( -\sqrt{3}\right)\implies \theta =
\begin{cases}
\frac{2\pi }{3}\leftarrow \\
\frac{5\pi }{3}
\end{cases}

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

thus         \bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]
5 0
3 years ago
Question: Find m HK...
Serhud [2]

Answer:

104degrees

Step-by-step explanation:

From the given diagram, line LJ bisects KN, hence arcKL = arcHJ

Given

arHJ = 4x

arc KJ = x+39

Equating both

4x = x+39

4x - x = 39

3x = 39

x = 39/3

x = 13

Since arcHK = arcHJ + arcKJ

arcHK = x+39+4x

arcHK = 5x+39

arcHK = 5(13) + 39

arcHK = 65+39

arcHK = 104degrees

Hence the measure of arcHK is 104degrees

7 0
3 years ago
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