Answer:
Step-by-step explanation:
you can use the equation point-slope of a line
(y-y1)= m(x-x1)
m is the slope =rise /run
to get from the lower point on the line to the other you rise 4 units and run -6 units so m= -4/6= -2/3
now that you have the slope pick you need one point
pick any poin on the line for example (-4, -1)
now you substitute into the point-slope equation point (-4,-1) and slope -2/3
(y+1)= -2/3(x+4)
in standard form will be
y=
y=
Answer:
The Taylor series of f(x) around the point a, can be written as:
Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as: