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4 years ago

Need help on this ASAPPPPP

Mathematics

2 answers:

Alex787 [66]4 years ago

4 0

It’s B i am pretty sure

lord [1]4 years ago

3 0

Answer: B

Step-by-step explanation:

Over to the right 5 and down 2

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REALLY NEED HELP ON THESE!!

nata0808 [166]

The answer would be 56n^2 + 19n - 15

Multiply 8n with 7n to get 56n^2, then multiple 8n with 5 and you get 40n, then multiple -3 with 7n to get -21n, then -3 times 5 which gives you -15. Simplify and that is the answer you would get.

6 0

4 years ago

Find the measure of x. 8.3 340 х x = [?] Round to the nearest tenth.

Tresset [83]

Answer:

5.6 =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side/ adj side

tan 34 = x / 8.3

8.3 tan 34 = x

5.59842 = x

To the nearest tenth

5.6 =x

3 0

3 years ago

What is the square root of nine

antoniya [11.8K]

The square root of nine is 3.

8 0

3 years ago

Read 2 more answers

What is the midpoint of the segment shown below?

Papessa [141]

B bro it b just trust I promise it b

4 0

4 years ago

I need help i’m failing math!!!

adell [148]

Answer:

$\huge\boxed{\bf\:2\sqrt{5} \:\: units }$

Step-by-step explanation:

We have a figure given in the shape of a square with a diagonal (x) passing from one edge to another. We need to find the measure of its diagonal if the side of the square is $\sqrt{10}$ units.

We know that, a square has all equal sides. Then, all the sides of the square will be equal to $\sqrt{10}$ units.

Now, let's find the diagonal.

To find the diagonal of a sqaure from one of its sides, we need to know the formula ⟶ Diagonal = side $\bf\:\sqrt{2}$ .

By using this formula,

$Diagonal (x)\\= side *\sqrt{2} \\= \sqrt{10} *\sqrt{2}\\ = \sqrt{5*2*2} \\= \boxed{\bf\:2\sqrt{5} \:units}$

→ The diagonal of the square = 2√5 units.

$\rule{150pt}{2pt}$

5 0

3 years ago