Lagrangian:

where the function we want to minimize is actually

, but it's easy to see that

and

have critical points at the same vector

.
Derivatives of the Lagrangian set equal to zero:




Substituting the first three equations into the fourth gives


Solving for

, we get a single critical point at

, which in turn gives the least distance between the plane and (0, 2, 5) of

.
Answer:
GH=15
Step-by-step explanation:
HK= FK/2= 16/2= 8
Using pythagoras theorem in triangle GHK,
GH²= GK²-HK²
= 17²-8²
= 225
GH= √225
=15
Answer: It is possible to draw different lines to approximate the same data. The line of best fit is only an estimate.