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3 years ago

There are 24 hours in a day and 7 days in a week. Write an expression to show how many hours there are in t weeks.

1 answer:

4 0

To set the equation, we can first find out hiw many hours there are in a week by mutiplying 7 by 24:

7 × 24 = 168

For t weeks, we can mutiply t by the above answer:

168 × t
=168t

Therefore the answer is 168t.

Hope it helps!

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-1/2x-3=4<br> Solve for x

sleet_krkn [62]

Answer:

x=-3.5

reason:

first, add 3 to both sides
this makes the equation -1/2x=7
then, divide both sides by -1/2
this will give you x=-3.5

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3 years ago

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A problem states “ there are nine more children than parents in a room. There are 25 people in the room and all. How many childr

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

If C represents the number of children you aren't gonna want to multiple like how it shows in option b and you aren't gonna wanna subtract.

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3 years ago

Simplify x to the 1/3 power (x to the 1/2 power + 2x to the 2 power )

OverLord2011 [107]

Answer:

x^(5/6) + 4(x^(7/3))

Step-by-step explanation:

Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )

Simplify x^(1/3) × (x^(1/2) + (2x)^2)

= x^(1/3)(x^(1/2)) + x^(1/3)((2x)^2)

= x^(1/3+1/2) + 4(x^(1/3+2))

= x^(5/6) + 4(x^(7/3))

x^(1/3) is y such that y^3 = x

(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x

x^(1/2) = √2 = y such that y^2 = x

(2x)^2 = 4x^2

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3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

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3 years ago

Round 5.9496 to the nearest thousandth

Evgesh-ka [11]

Answer:

5.95

Step-by-step explanation:

that is because 96 is rounded too 100

so its 5.9500 = 5.95

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