Using asa you find that wx=xw and then angle rwx is equal to angle wxv bc of alternate interior angles and then angle xwv is equal to angle rxw also bc of alt int angles
Answer:
y = 234t
Step-by-step explanation:
Divide the equation by t on both sides. See image.
Answer:
It was approximately a 9% decrease. (If you need to round to the nearest tenth, 9.1. If you need to round to the nearest hundredth, 9.10).
Step-by-step explanation:
I am going to assume that the question means that Andrea could have earned 220 points on the assignment, but instead because the assignment was late, she was marked down 20 points. (Reduced to 20 points is kind of awkward wording).
Given that, 20 divided by 220 comes out to 0.0909 repeating.
0.09, as a percentage, is 9%. (Again, 0.0909, 9.09%, could be rounded up to 9.1%).
Hope this helps!
With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that
![I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx](https://tex.z-dn.net/?f=I%20%3D%20%5Cdisplaystyle%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7B%5Csqrt%5B%5Cphi%5D%7Bx%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7B%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx%20%3D%20%5Cint_0%5E%5Cinfty%20%5Cfrac%7Bx%5E%7B%5Cphi-1%7D%20%5Ctan%5E%7B-1%7D%28x%29%7D%7Bx%20%281%2Bx%5E%5Cphi%29%5E2%7D%20%5C%2C%20dx)
Replace 
:
Split the integral at x = 1. For the integral over [1, ∞), substitute 
:
The integrals involving tan⁻¹ disappear, and we're left with
