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Ket [755]
3 years ago
10

Hii please help i’ll give brainliest!!

Mathematics
2 answers:
cupoosta [38]3 years ago
7 0

Answer:

A

I Had that question before

marshall27 [118]3 years ago
4 0
I say A but sorry if it’s wrong
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You are making an audience selection. The first selection narrows your audience of 240,000 by 25% and the next selection narrows
vlada-n [284]

Answer:

the answer is c. 108,000

Step-by-step explanation:

240,000×25%=60,000

240,000-60,000=180,000

180,000×40%=72,000

180,000-72,000=108,000

your answer is 108,000

8 0
2 years ago
25 is what percent of 365
kondaur [170]
\begin{array}{ccc}365&-&100\%\\25&-&x\%\end{array}\ \ \ |cross\ multiply\ both\ sides\\\\365\cdot x=25\cdot100\\365x=2500\ \ \ \ \ |divide\ both\ sides\ by\ 365\\\\x=\frac{2500}{365}\\\\x=\frac{2500:5}{365:5}=\frac{500}{73}=\boxed{6\frac{62}{73}\ (\%)\approx7\%}
3 0
2 years ago
Read 2 more answers
Find the sum of each set of numbers, as well as the size n of each set of numbers (n = number of numbers in the set). Use these
guapka [62]

We have to add numbers without a calculator.

1) 25, 35, 19, 31

We can group them by the last digit, so they are easy to add:

25 + 35 = 20 + 30 + 5 +5 = 50 + 10 = 60

19 + 31 = 10 + 30 + 9 +1 = 40 + 10 = 50

Then, 60 + 50 = 110

numbers in the set n = 4

Sum = 110

2) 101, 73, 49, 27, 24, 36

We can group them again by the last digit (adding 10, like the previous example).

We can substract the last digit from one number and add it to the other one. The result will be the same, but they will become easier to add.

101 + 49 = 100+50 = 150

73 + 27 = 70 + 30 = 100

24 + 36 = 20 + 40 = 60

150 + 100 + 60 = 250 + 60 = 310

numbers in the set n = 6

Sum = 310

3) 25, 25, 25, 30, 30, 30, 32, 32, 32

In this case we have 3 times the same numbers, so we can add the three different numbers and then multiply the total by 3.

We can use the properties of the multiplication to simplify the product (we will use the distributive property)

25 + 30 + 32 = 27 + 30 + 30 = 87

87 * 3 = 80*3 + 7*3 = 240 + 21 = 261

numbers in the set n = 9

Sum = 261

8 0
1 year ago
If a^20=(a^n)^m what are the values for m and n
Alinara [238K]
N = 2 and m=10. You multiply them
7 0
3 years ago
I need help with the last two !!!
Dmitriy789 [7]

Step-by-step explanation:

G(x) = - x^2 + 10x

a + G(a) = a - a^2 + 10a = - a^2 + 11a or 11a - a^2 or a(11 - a)

1/G(a) = 1/(10a - a^2) = 1/a(10 - a)

6 0
2 years ago
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