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g100num [7]
3 years ago
12

There are 5 ways to drive from Town X to Town Y. There are 3 ways to drive from Town Y to Town Z. How many different ways are th

ere to drive from Town X to Town Z, passing through Town Y?
Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:

A

Step-by-step explanation:

I took the test

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Ype the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
rewona [7]

Answer:

4/8 or 1/2

Step-by-step explanation:

Convert all size to x/8

1/4=2/8 and 1/2=4/8

Multiply size of beaker by how many there are filled

1/8 * 2= 2/8

2/8*7= 14/8

4/8*3 =12/8

then add all of them together = 28/8

convert 4 liters to 32/8

Subtract 32/8 - 28/8 = 4/8

4 0
3 years ago
Mike traveled from the school to the mall and then from the mall to the library. Henry traveled from the school to the library.
Natalija [7]

Answer:

12 miles

Step-by-step explanation:

From the graph given :

Mike's travel :

School to Mall= 16 miles

Mall to Library = 30 miles

Total travel = 16 + 30 = 46 miles

Henry's travel :

From school to Library = Hypotenus :

Distance can be obtained using Pythagoras :

Hypotenus = √(opposite² + adjacent²)

Hypotenus = √(30² + 16²)

Hypotenus = √1156

Hypotenus = 34 miles

Difference in Distance covered :

(46 miles - 34 miles) = 12 miles

4 0
3 years ago
The fuel efficiency for a 2007 passenger car was 31.2 mi/gal. For the same model of car, the fuel efficiency increased to 35.6 m
Ierofanga [76]

We have been given that fuel efficiency for a 2007 passenger car was 31.2 mi/gal and the same model of car, the fuel efficiency increased to 35.6 mi/gal in 2012. Also, the gas tank for this car holds 16 gallons of gas.

We need to write a function and graph a linear function that models the distance that each car can travel for a given amount of gas up to one tankful.

Let represent the functions as d_{1}(x) and d_{2}(x)  where d_{1} and d_{2} represent the distances traveled by car in years 2007 and 2012 and x represents the number of gallons. Therefore, we can express the required functions as:

d_{1}(x)=31.2x \text{ and } d_{2}(x) = 35.6x

Domain of both these functions are [0,16] and ranges are [0,499.2] and [0,569.6] respectively for years 2007 and 2012.

The difference function will be:

f(x)=35.6x-31.2x\\
f(x)=4.2x

f(16)=4.2*16=67.2

Domain of this function is [0,16] and range is [0,67.2].

The graphs are shown below.


3 0
3 years ago
What does -2/3 (x + 5) + 4 (x + 5) - 10/3 (x + 5) equal
Kitty [74]

Answer: 0

Step-by-step explanation:

-\frac{2}{3}(x+5)+4(x+5)-\frac{10}{3}(x+5) = ?

-\frac{2}{3}x-\frac{10}{3}x+4x+20-\frac{10}{3}x-\frac{50}{3} = ?

(-\frac{2}{3}x+4x -\frac{10}{3}x) +(-\frac{10}{3}+20-\frac{50}{3})=?

(-\frac{12}{3}x+4x)+(-\frac{60}{3}+20)=?\\  (-4x+4x)+(-20+20)=?\\0+0=0

4 0
3 years ago
Identify the restrictions on the domain of f(x) = quantity x minus 3 over quantity x plus 5. x ≠ 5 x ≠ −5 x ≠ 3 x ≠ −3
Fantom [35]

Answer:

x ≠ - 5

Step-by-step explanation:

Given

f(x) = \frac{x-3}{x+5}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be.

solve : x + 5 = 0 ⇒ x = - 5 ← excluded value

6 0
3 years ago
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