Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :
Putting all the values, we get :
Hence, the minimum allowed length for the runway is 117.33 m.
The answer to number 17 is c
(X-10)(X-10)
You need to first multiply out the brackets. So, first times X by X, which makes x^2 . Then do -10 x -10 which makes 100. You then need to multiply the X within the first bracket with the minus 10 in the second bracket which makes -10x. Do the same but with the -10 from the first bracket and the X from the second which again makes -10x. So altogether you have x^2-10x-10x+100. This can be simplified down to x^2-20x+100. You then do the same thing for the second question :)
Answer:
fyjjnbvfddddddddfghjkjhg
Step-by-step explanation:
Answer:
-54
Step-by-step explanation:
x / 9 = -6....multiply both sides by 9, eliminating the 9 on the left side
x = -6 * 9
x = -54 <===
