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1 year ago

5

You have an object with a mass of 5 kg. If it has a velocity of 4.7 m/s, what distance will the object travel if 98 newtons are

applied to stop it?

1 answer:

professor190 [17]1 year ago

6 0

69,420 ------------------------------------------------------------------------

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6th grade math <br><br> 3m + 4m + 5 + 1 -7m

elena55 [62]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the 4th term of the expanded binomial (2x – 3y)^6

san4es73 [151]

Answer:

The 4th term of the expanded binomial is $-4320x^3y^3$

Step-by-step explanation:

Considering:

$(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k}y^k$

$(2x-3y)^6 = \sum_{k=0}^{6} \binom{6}{k} (2x)^{6-k}(-3y)^k$

Now, you gotta calculate for every value of $k$

$(2x-3y)^6 = \binom{6}{0} (2x)^{6-0}(-3y)^0 + \binom{6}{1} (2x)^{6-1}(-3y)^1 + \binom{6}{2} (2x)^{6-2}(-3y)^2 + \\$

$\binom{6}{3} (2x)^{6-3}(-3y)^3 + \binom{6}{4} (2x)^{6-4}(-3y)^4 + \binom{6}{5} (2x)^{6-5}(-3y)^5 + \binom{6}{6} (2x)^{6-6}(-3y)^6$

I will not write every product, but just solve following the steps:

For $k=0$

$\binom{6}{0} (2x)^{6-0}(-3y)^0$

$\frac{6!}{(6-0)!(0!)} (2x)^{6-0}(-3y)^0$

$\frac{6!}{6!} \left(2x\right)^{6-0}\cdot 1$

$1\cdot \:1\cdot \left(2x\right)^{6-0}$

$2^6x^6$

$64x^6$

$(2x-3y)^6=64x^6-576x^5y+2160x^4y^2-4320x^3y^3+4860x^2y^4-2916xy^5+729y^6$

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2 years ago

I cannot understand this AT ALL. for some reason..help?

Radda [10]

Answer:

Step-by-step explanation:

1) 1.49/3=.49 each

2)12(5x+4)-(24-12)

60x+48-24+12 (dont forget to distribute the negative sign)

60x+36

3)1.24/4=.31

.31x6=1.86

4)17+(-28)

same thing as saying 17-28=-11

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3 years ago

Please explain how to check the solution for y=x-3

adell [148]

Answer:

Just put it in the format and you will eventually find it.

Step-by-step explanation:

Hope this helps.

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2 years ago

I’ll give the Brainliest to who answers this question with a reasonable explanation.

Anna35 [415]

Answer:

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Step-by-step explanation:

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2 years ago

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