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7nadin3 [17]
2 years ago
5

You have an object with a mass of 5 kg. If it has a velocity of 4.7 m/s, what distance will the object travel if 98 newtons are

applied to stop it?
Mathematics
1 answer:
professor190 [17]2 years ago
6 0

69,420 ------------------------------------------------------------------------

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Jacob’s daily tips this work week were $99, $78, $58, $91, $90, and $68. Is Jacob correct in thinking that the mean best represe
Neko [114]

Answer:

D. No, Jacob is not correct. The median amount he makes is $84.00 in a day.

Step-by-step explanation:

In this case, the mean is not the best measure of this data.

We can see that there is one value lower than the rest, $58.  This brings the mean down.

With the value of $58, the mean is $80.70.  If we were to take this value out, the mean would be $85.20, which is higher.

Since the mean is brought down by this value, we should use the median.  The median of this data set is $84.

6 0
3 years ago
Read 2 more answers
A seed company planted a floral mosaic of a national flag. The perimeter of the flag is 2,360 ft Determine the​ flag's width and
just olya [345]

The length of rectangular mosaic flag is 710 feet and width is 470 feet

Step-by-step explanation:

Let l be the length of the flag

and

w be the width

Then according to given statement

l = w+240

Perimeter = 2360 feet

The formula for perimeter is given by:

Perimeter = 2(Length+Width)

Putting values

2360 = 2[w+240+w]\\\frac{2360}{2} = \frac{2[w+240+w]}{2}\\1180 = 2w+240\\1180-240 = 2w+240-240\\940 = 2w

Dividing both sides by 2

\frac{2w}{2} = \frac{940}{2}\\w = 470

The width is 470 feet

Now,

l = w+240\\= 470+240\\=710

Hence,

The length of rectangular mosaic flag is 710 feet and width is 470 feet

Keywords: Perimeter, dimensions

Learn more about perimeter at:

  • brainly.com/question/9527422
  • brainly.com/question/9381523

#LearnwithBrainly

4 0
3 years ago
Find the length of the missing side. Leave your answer in simplest radical form.
lozanna [386]

Answer:

The other side is 7.48 yards.

Step-by-step explanation:

Given that,

Hypotenuse = 15 yards

One leg = 13 yards

We need to find the length of the other leg. We can use the Pythagoras theorem to find it such that,

H^2=b^2+h^2

Where

h is other leg

Put all the values,

h=\sqrt{H^2-b^2} \\\\h=\sqrt{(15)^2-(13)^2} \\\\h=7.48\ yd

So, the other side is 7.48 yards.

6 0
3 years ago
Please help me please I really need help
Slav-nsk [51]
I can’t the picture can you post a other one
4 0
2 years ago
I need help............​
Alexxandr [17]

Problem 35

The bar graph is shown below

You simply draw various rectangles such that the heights represent the frequency of each animal type.

Eg: there are 20 elephants, so the "elephant" bar is 20 units tall.

You can make the bar graph by hand, or use spreadsheet software. I recommend going with software (if you can).

=======================================================

Problem 36

1 book = 20 mm thickness

5 books = 5*20 = 100 mm thickness

1 paper = 0.016 mm thickness

5 papers = 5*0.016 = 0.08 mm thickness

total thickness = 100+0.08 = 100.08 mm

<h3>Answer: 100.08 mm</h3>

=======================================================

Problem 37

121/11 = 11

121 = 11*11

If we say 11+11+11+...+11, and have 11 copies of these values added, then we get to a sum of 121

This is probably the easiest way to get the answer assuming repeated values are allowed.

You can stop here if your teacher allows you to use repeated values. If not, then move onto the next section.

-----------

If your teacher requires you to add 11 <u>different</u> numbers, then you can follow this procedure

  1. Write out eleven copies of "11" in a sequence
  2. Subtract 2 from the first "11" (to get 9) and add it to the last copy of "11" (to get 13)
  3. Subtract 4 from the second "11" (to get 7) and add it to the second to last copy of "11" (to get 15)
  4. Subtract 6 from the third "11" (to get 5) and add it to the third to last copy of "11" (to get 17)
  5. Subtract 8 from the fourth "11" (to get 3) and add it to the fourth to last copy of "11" (to get 19)
  6. Finally, subtract 10 from the fifth "11" (to get 1) and add it to the fifth to last copy of "11" (to get 21)

After carefully following those steps, you'll get this sequence (in the exact order shown):

{9, 7, 5, 3, 1, 11, 21, 19, 17, 15, 13}

There are three properties to notice of this sequence

  1. It's composed of two decreasing arithmetic sequences {9, 7, 5, 3, 1} and {21, 19, 17, 15, 13}
  2. The 11 in the middle hasn't been changed from the original sequence of nothing but "11"s.
  3. You should find that the terms of this new sequence add to 121.

That sequence we got sorts to {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21}

and we can say 1+3+5+7+9+11+13+15+17+19+21 = 121

<h3>Answer: 1+3+5+7+9+11+13+15+17+19+21 = 121</h3>

5 0
2 years ago
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