Question

ASAP please it’s very important

Answer 1

Answer:

x = 30° and 330°

Step-by-step explanation:

Assuming the intervals is {0 , 2π} or {0° , 360°}

$tan\ x=\frac{-\sqrt{3} }{3} \\\\x=tan^{-1} (\frac{-\sqrt{3} }{3})\\\\x = -30$

So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant

so the two solutions are

x = 30° and 330° or

$x=\frac{\pi }{6}\ radians\ \ , \ \ \frac{11\pi }{6}\ radians$