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aliina [53]
3 years ago
9

A chocolate manufacturing company produces two types of chocolate: A and B. Ingredients required for manufacturing the products

include milk and cacao only . Each unit of type A chocolate requires 2 units of milk and 4 units of cacao. Each unit of type B chocolate requires 1 units of milk and 3 units of cacao. The company's production plant has a total of 22 units of milk and 46 units of cacao available. On each sale the company makes a profit of $6.20 for every unit of chocolate of type A and $4.20 for every unit of type B. Develop a linear programming model to determine the manufacturing quantity for each type in order to maximize profit..

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

The maximum profit is when they make 10 units of A and 2 units of B.

Step-by-step explanation:

Let x is units of milk

Let y units of cacao

Given that :

The company's production plant has a total of 22 units of milk and 46 units of cacao available.

2x + y ≤ 22 (2 unit of milk for each of A and 1 for B; 22 units available)

4x + 3y ≤46 (4 unit of milk for each of A and 3 for B; 46 units available

Graph the constraint equations and find the point of intersection to determine the feasibility region.

The intersection point (algebraically, or from the graph) is (10, 2)

The objective function for the problem is the total profit, which is $6.2 per unit for A and $4.2 per unit for B: 6.2x + 4.2y.

Hence, we substitute (10, 2)  into the above function:

6.2*10 + 4.2*2 = 70.4

The maximum profit is when they make 10 units of A and 2 units of B.

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tino4ka555 [31]

Answer:

Equation: 810= (90 + 24y)

y = 30 hours

Step-by-step explanation:

Given:

Site visit = $45 per site

cost per hour worked = $24

for <u>each </u>work site, the total amount of money earned

= site visit fee + cost for working

But the question mentions TWO sites, hence there will be two site visits. Therefore for TWO sites, we have to account for TWO site visit fee.

Therefore for TWO sites, the total amount of money earned

= site 1 visit fee + site 2 visit fee + cost for working

= (2 x site visit fee) +  cost for working  ------ Equation 1

We are further given that we worked y hours at the hourly work rate of $24 per hour.

Hence the cost for working

= y hours x hourly rate

= y   x   $24

= $24y   (substituting this into equation 1 above)

for TWO sites, the total amount of money earned

= (2 x site visit fee) +  cost for working

= (2 x $45) +  $24y

= $90 + $24y

= $(90 + 24y)

We are also given that we have to earn $810 for two sites, hence

810 = 90 + 24y    

810 - 90 = 24y

24y = 720

y = 720/24

y = 30 hours

8 0
3 years ago
Can somebody please help we with this math problem
Olin [163]
I THINK THE CORRECT ANSWER IS A!!!
4 0
3 years ago
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Last year, Nicholas started babysitting to earn extra spending money. Over the summer, he tracked how much money he earned at ea
Ierofanga [76]

Answer:

25%

Step-by-step explanation:

The 5 values of the given box plot are;

The minimum value = 20

The first quartile, the 25th percentile point, Q₁ = 25

The median or second quartile, the 50th percentile point, Q₂ = 30

The third quartile, the 75th percentile point, Q₃ = 40

The maximum value = 55

The range = The maximum value - The minimum value

∴ The range = 55 - 20 = 35

We note that Nicholas earned $25 or less from the minimum value up to first quartile, Q₁, which is the 25th percentile point, where we have 25 percent of the data points

Therefore, the percent of the time Nicholas earned $25 or less is 25 percent of the time.

8 0
2 years ago
A right rectangular prism is shown. The two dimensional net is also shown. Find the surface area of this prism.
Natasha_Volkova [10]

Hey!

------------------------------------------------

Surface Area Formula: 2LW * 2LH * 2WH

------------------------------------------------

2LW:

5 x 1 = 5

5 x 2 = 10

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2LH:

4 x 1 = 4

4 x 2 = 8

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2WH:

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20 x 2 = 40

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Surface Area:

40 + 8 + 10= 58

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Answer:

D) 58 cm2

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Hope This Helped! Good Luck!

5 0
3 years ago
F(x)+2x^2-4x-3 g(x)=2x^2-16 find f(x)+g(x)
AveGali [126]
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3 0
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