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aliina [53]
3 years ago
9

A chocolate manufacturing company produces two types of chocolate: A and B. Ingredients required for manufacturing the products

include milk and cacao only . Each unit of type A chocolate requires 2 units of milk and 4 units of cacao. Each unit of type B chocolate requires 1 units of milk and 3 units of cacao. The company's production plant has a total of 22 units of milk and 46 units of cacao available. On each sale the company makes a profit of $6.20 for every unit of chocolate of type A and $4.20 for every unit of type B. Develop a linear programming model to determine the manufacturing quantity for each type in order to maximize profit..

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

The maximum profit is when they make 10 units of A and 2 units of B.

Step-by-step explanation:

Let x is units of milk

Let y units of cacao

Given that :

The company's production plant has a total of 22 units of milk and 46 units of cacao available.

2x + y ≤ 22 (2 unit of milk for each of A and 1 for B; 22 units available)

4x + 3y ≤46 (4 unit of milk for each of A and 3 for B; 46 units available

Graph the constraint equations and find the point of intersection to determine the feasibility region.

The intersection point (algebraically, or from the graph) is (10, 2)

The objective function for the problem is the total profit, which is $6.2 per unit for A and $4.2 per unit for B: 6.2x + 4.2y.

Hence, we substitute (10, 2)  into the above function:

6.2*10 + 4.2*2 = 70.4

The maximum profit is when they make 10 units of A and 2 units of B.

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VladimirAG [237]

Answer:

B, C, D hope this helps btw are you from connexus?

Step-by-step explanation:

7 0
3 years ago
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Rzqust [24]
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8 0
3 years ago
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Workout and simplify
Step2247 [10]

Answer:

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7 0
3 years ago
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Ok,....My daughter is having a problem.... So am I,
egoroff_w [7]
Bruh
so toal cost=28 right?

total cost=total cost of water+total cost of tickets
water=3
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28=3+total cost of tickets
remember we can do anything to an equaton as long as you do it to both sides

28=3+total cost of tickets
subtract 3 from both sides
28-3=3-3+total cost of tickets
25=0+cost of tickets
25=cost of tickets

if he bought 5 tickets, how much does each cost
25=5tickets
divide both sides by 5
25/5=5/5tickets
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answer is 1 ticket cost $5.00

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7 0
3 years ago
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Please help answer this
yuradex [85]

I think you can use cosine rule if only the lines that form the <52 are equal.

6 0
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