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aliina [53]
3 years ago
9

A chocolate manufacturing company produces two types of chocolate: A and B. Ingredients required for manufacturing the products

include milk and cacao only . Each unit of type A chocolate requires 2 units of milk and 4 units of cacao. Each unit of type B chocolate requires 1 units of milk and 3 units of cacao. The company's production plant has a total of 22 units of milk and 46 units of cacao available. On each sale the company makes a profit of $6.20 for every unit of chocolate of type A and $4.20 for every unit of type B. Develop a linear programming model to determine the manufacturing quantity for each type in order to maximize profit..

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

The maximum profit is when they make 10 units of A and 2 units of B.

Step-by-step explanation:

Let x is units of milk

Let y units of cacao

Given that :

The company's production plant has a total of 22 units of milk and 46 units of cacao available.

2x + y ≤ 22 (2 unit of milk for each of A and 1 for B; 22 units available)

4x + 3y ≤46 (4 unit of milk for each of A and 3 for B; 46 units available

Graph the constraint equations and find the point of intersection to determine the feasibility region.

The intersection point (algebraically, or from the graph) is (10, 2)

The objective function for the problem is the total profit, which is $6.2 per unit for A and $4.2 per unit for B: 6.2x + 4.2y.

Hence, we substitute (10, 2)  into the above function:

6.2*10 + 4.2*2 = 70.4

The maximum profit is when they make 10 units of A and 2 units of B.

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What is the solution to the inequality -4x < 8? x < -24 x > -24 x < -2 x > -2
liberstina [14]

Answer:

x > -2

Step-by-step explanation:

Solve the inequality -4x < 8 using inverse operations. If you divide or multiply by a negative, flip the inequality sign.

-4x < 8\\\\\frac{-4x}{-4} < \frac{8}{-4}

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8 0
3 years ago
Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.
Masja [62]

Answer:

See below.

Step-by-step explanation:

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\sec(\theta)=-2/\sqrt{3}

Recall that secant is simply the reciprocal of cosine. So we can:

\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

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6 0
3 years ago
What is the equation of a line perpendicularto y=-2/5x-1 that passes through(2,-8)​
Andrews [41]
<h2>Answer: y =  ⁵/₂ x - 13   OR  y + 8 =  ⁵/₂ x - 5 </h2>

<h3>Step-by-step explanation:</h3>

<u>Find the slope of the perpendicular line</u>

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are <em>negative-reciprocal</em>s of each other.

⇒  if the slope of this line = - ²/₅

      then the slope of the perpendicular line (m) = ⁵/₂

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

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                                   ∴  y + 8 = ⁵/₂ (x - 2)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                  since   y + 8 =  ⁵/₂ (x - 2)

                                    y =  ⁵/₂ x - 13

7 0
3 years ago
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