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3 years ago

PLEASE HELP MEEEEEEEE ILL MARK YOU BRAINLIEST

Mathematics

2 answers:

Rudiy273 years ago

8 0

Answer:

5.60

Step-by-step explanation:

To find what 10 pens cost we have to go down to the cost of 1 pen first.

If 3 pens costs 1.68 then the cost of 1 pen is 1.68 divided by 3.

$\frac{1.68}{3} = 0.56$

If one pen costs 0.56 then 10 pens cost 0.56 multiplied by 10.

0.56 × 10 = 5.60

Andre45 [30]3 years ago

5 0

Answer:

16.8

Step-by-step explanation:

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A ticket to a movie theatre for a student is $7. The cost for an adult is $2 more than for a student. How much would it cost 13

MakcuM [25]

Answer: it would cost a total of $194

Step-by-step explanation:

A ticket to a movie theatre for a student is $7. The cost for an adult is $2 more than for a student.

If student ticket costs $x, adult ticket would cost x + 2

This means that the cost for an adult is

7 + 2 = $9

The cost of 13 adult tickets to the movie theatre would be

13 × 9 = $117.

The cost of 11 student tickets to the movie theatre would be

11 × 7 = $77

Total cost of 13 adult tickets and 11 student tickets would be

117 + 77 = $194

3 0

3 years ago

What is 8% of 37...........

docker41 [41]

Answer:

2.96

Explanation:

37/x=100/8

(37/x)*x=(100/8)*x - we multiply both sides of the equation by x

37=12.5*x - we divide both sides of the equation by (12.5) to get x

37/12.5=x

2.96=x

x=2.96

7 0

3 years ago

Read 2 more answers

A rectangle has a length of 6.5m and a width of 7.3m what is the area and the perimeter

Bad White [126]

Step-by-step explanation:

<h3>Given:</h3>

Length of the rectangle = 6.5 m

Width of the rectangule = 7.3 m

First case,

Area of the rectangle

= length × width

= 6.5 m × 7.3 m

= 47.45 sq.m (Ans)(i)

Second case,

Perimeter of the rectangle

= 2(length + width)

= 2(6.5 + 7.3)m

= 2 × 13.8 m

= 27.6 m (Ans)(ii)

5 0

3 years ago

Read 2 more answers

The number of pastries produced by a bakery can be represented by

antiseptic1488 [7]

Answer:

where are the others

Step-by-step explanation:

is there supposed to be other numbers?

3 0

3 years ago

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

3 years ago