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Aliun [14]
3 years ago
7

What are the truck ID’s of trucks that have carried small shipments. Small shipments are defined as those that weigh less than 8

00 pounds? (HInt: Avoid duplcates.)
Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

Table for the question is attached in the picture below :

Answer:

SELECT distinct(TRUCK_ID), WEIGHT from SHIPMENT where WEIGHT < 800 ;

Step-by-step explanation:

The Structured query language (SQL) defined above, returns only the TRUCK_ID and Weight column from the shipment table as they are the only two columns listed after the select keyword. The condition is added using the WHERE keyword on the weight table, this filters the result returned to include only rows where the weight value is less than 800. The distinct keyword used alongside the TRUCK_ID column ensures that a certian TRUCK_ID value isn't returned more than once (Hence, it is used to avoid duplicates).

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Inga [223]
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3 0
3 years ago
15. The length of each edge of a regular tetrahedron,
grigory [225]

Slant height of tetrahedron is=6.53cm

Volume of the tetrahedron is=60.35\mathrm{cm}^{3}

Given:

Length of each edge a=8cm

To find:

Slant height and volume of the tetrahedron

<u>Step by Step Explanation: </u>

Solution;

Formula for calculating slant height is given as

Slant height=\sqrt{\frac{2}{3}} a

Where a= length of each edge

Slant height=\sqrt{\frac{2}{3}} \times 8

                     =\sqrt{0.6667} \times 8

                     =0.8165 \times 8=6.53cm

Similarly formula used for calculating volume is given as

Volume of the tetrahedron=\frac{a^{3}}{6 \sqrt{2}}

Substitute the value of a in above equation we get

Volume=\frac{8^{5}}{6 \sqrt{2}}

            =\frac{512}{6 \sqrt{2}}

            =\frac{512}{6 \times 1.414}

Volume=512 / 8.484=60.35\mathrm{cm}^{3}

Result:

Thus the slant height and volume of tetrahedron are 6.53cm and 60.35\mathrm{cm}^{3}

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Answer:

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