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2 years ago

What is the following states of the pythangorean theorom triangles

Mathematics

1 answer:

Vitek1552 [10]2 years ago

8 0

I don’t know if you were asking for that cause my english is not that good but i hope that i helped you

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HELP. PLEASE I put the coordinates but don't know what the answer is HELP ME

Sladkaya [172]

Answer:

Change b (0,4) the 4 goes to the top and c as well (0,1) the 1 goes on top as well and that should be right

Step-by-step explanation:

hope this helped

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3 years ago

A) Identify the center of rotation:<br> What points in the rotated image correspond with

Phoenix [80]

Answer:

the rotated image correspond is angle DEF

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2 years ago

WILL GIVE BRAINLIEST!!!

-BARSIC- [3]

Answer:

see below

Step-by-step explanation:

This means to be able to be given a word problem like: Jessica went to the store and spent $2.25 on candy, $2.50 on chips and $2.00 for a soda. How much did Jessica spend?

Given this you are able to write: $2.25 + $2.50 + $2.00 = $6.75

4 0

3 years ago

Read 2 more answers

Write an equation ( in slope form or point slope form) of a line with slope 1/2 that passes through the point (-4,-7)

bija089 [108]

Answer:

x(1/2)-5

Step-by-step explanation:

8 0

3 years ago

Lily swims for 5 hours in stream that has a current of 1 mph. She leaves her dock, swims upstream for 2 miles and then swim back

antiseptic1488 [7]

Answer:

Swimming speed in still water is approximately 1.5 mph

Step-by-step explanation:

Given the speed of the current = 1 mph

distance she swims upstream =2 miles,

the total time = 5 hours.

She swam 2 miles upstream against the current and 2 miles back to the dock with the current. The formula that relates distance, time, and rate is $d = r t\ \ \ \ or \ \ \ t= \frac{d}{r}$

Let x be the speed in still water.

Then her speed with the current is x + 1, and

her speed against the current is x – 1.

Total time is equal to 2 miles with upstream and 2 miles downstream.

$\frac{2}{x+1}+\frac{2}{x-1}=5\\\\\frac{2(x-1)}{(x+1)(x-1)}+\frac{2(x+1)}{(x-1)(x+1)}=5\\\\\frac{2x-2}{(x^2-1)}+\frac{2x+2)}{(x^2-1)}=5\\\\\frac{2x-2+2x+2)}{(x^2-1)}=5\\\\4x=5(x^2-1)\\4x= 5x^2-5\\0= 5x^2-4x-5$

Now Using quadratic formula to solve above equation we get;

$x= \frac{-b \±\sqrt{b^2-4ac}} {2a}\\\\here \ \ a= 5,b=-4,c=-5\\\\x= \frac{-(-4) \±\sqrt{(-4)^2-4\times 5\times-5}} {2\times5}\\\\x=\frac{4 \±\sqrt{16+100}} {10}\\\\x=\frac{4 \±\sqrt{116}} {10}=x=\frac{4 \±2\sqrt{29}} {10}= x=\frac{2 \±\sqrt{29}} {5}\\ x \approx 1.5 \ or \ x = -0.7$

Since speed must be positive, Hence speed of still water is about 1.5 miles per hour.

3 0

3 years ago