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3 years ago

The equation for this graph has a leading coefficient that is

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Answer:

negative

Step-by-step explanation:

stepladder [879]3 years ago

5 0

Answer:no graph attached

Step-by-step explanation:

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ohn is interested in purchasing a multi-office building containing five offices. The current owner provides the following probab

Galina-37 [17]

Answer:

$28,875

Step-by-step explanation:

The given table is:

$\left|\begin{array}{c|cccccc}$Number of Lease Offices&0&1&2&3&4&5\\$Probability&5/32&3/16&3/32&1/4&9/32&1/32\end{array}\right|$

The expected probability is derived using the formula: $\sum_{i=0}^{5}x_iP(x_i)$

Therefore, for the given distribution,

Expected Probability

$=(0*\frac{5}{32})+ (1*\frac{3}{16})+ (2*\frac{3}{32})+ (3*\frac{1}{4})+ (4*\frac{9}{32})+ (5*\frac{1}{32})\\=2.40625$

If each yearly lease is $12,000

The Expected Yearly Lease for the Whole Building=2.40625 X 12000

=$28,875

4 0

3 years ago

Jason wrote this expression to describe the total amount he will spend on a magazine and a book.

kati45 [8]

The 11 may represent the price of the magazine if all the magazines at a certain store are $11. Then the s may represent the price of a book because all the books at a bookstore are different prices.

Hope this helps

8 0

4 years ago

Read 2 more answers

F(x)=-5x+8 What value of x would make f(x)=23? Need Answers ASAP

EastWind [94]

Answer:

-3

Step-by-step explanation:

23=-5x+8

23-8=-5x

15=-5x

x=-3

7 0

3 years ago

Read 2 more answers

What is a linear expression?

kondaur [170]

It either means its constant or the product of a constant

6 0

4 years ago

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

5 0

3 years ago