Answer:
-6 degrees F
Step-by-step explanation:
We start with -8F as the temperature. It fell 10 degrees to 2F, then fell 8 degrees to -6F.
Hello,
1: dom f=R
2: img f =R
3: 2x²-x-6=2(x²-2x/4+1/46)-6-1/8=2(x-1/4)²-49/8
Vertex=(1/4,-49,8)
4: roots are -3/2 and 2
2(x-1/4)²-49/8=1/8[(4x-1)²-49]=1/8*(4x+6)(4x-8)
5:
From the vertex to ∞
[-1/4 , ∞)
Answer:
Step-by-step explanation:
Step 1: Identify the GCF of the polynomial.
Step 2: Divide the GCF out of every term of the polynomial. ...
Step 1: Identify the GCF of the polynomial. ...
Step 2: Divide the GCF out of every term of the polynomial.
Step 1: Identify the GCF of the polynomial. ...
Step 2: Divide the GCF out of every term of the polynomial .
<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
