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Harrizon [31]
3 years ago
5

Simplify (√2)(3^√2)​

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

√2·3^√2

Step-by-step explanation:

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Which equation can be used to check whether 1/8 divided 6= 1/48?
S_A_V [24]

Answer:

Step-by-step explanation:

8 x 6 = 48 because you just add a 1

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The fraction 1/9 produces a repeating decimal 0.1 ? true or false
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The answer is true. 1/9 = 0.111111......
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X - (6.9) = 42.8<br><br> x = 42.8 +
Harman [31]
I hope this helps you



x=42.8+6.9



x=49.7
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3 years ago
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[HELP ASAP 50 POINTS] 17, 18, 19, 20
Charra [1.4K]

17) f(x) = 16/(13-x).

In order to find domain, we need to set denominator expression equal to 0 and solve for x.

And that would be excluded value of domain.

13-x =0

Adding x on both sides, we get

13-x +x = x.

13=x.

Therefore, domain is All real numbers except 13.



18).f(x) = (x-4)(x+9)/(x^2-1).

In order to find the vertical asymptote, set denominator equal to 0 and solve for x.

x^2 -1 = 0

x^2 -1^2 = 0.

Factoring out

(x-1)(x+1) =0.

x-1=0 and x+1 =0.

x=1 and x=-1.

Therefore, Vertical asymptote would be

x=1 and x=-1

19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)

We have degrees of numberator and denominator are same.

Therefore, Horizontal asymptote is the fraction of leading coefficents.

That is 7/2.


20) f(x)=(x^2+3x-2)/(x-2).

The degree of numerator is 2 and degree of denominator is 1.

2>1.

Degree of numerator >  degree of denominator .

Therefore, there would no any Horizontal asymptote.

6 0
3 years ago
The sum of a two digit number and the number obtained by interchanging the digits is 132. If the two digits differ by 2, find th
damaskus [11]

Answer:

A two-digit number can be written as:

a*10 + b*1

Where a and b are single-digit numbers, and a ≠ 0.

We know that:

"The sum of a two-digit number and the number obtained by interchanging the digits is 132."

then:

a*10 + b*1 + (b*10 + a*1) = 132

And we also know that the digits differ by 2.

then:

a = b + 2

or

a =  b - 2

So let's solve this:

We start with the equation:

a*10 + b*1 + (b*10 + a*1) = 132

(a*10 + a) + (b*10 + b) = 132

a*11 + b*11 = 132

(a + b)*11 = 132

(a + b) = 132/11 = 12

Then:

a + b = 12

And remember that:

a = b + 2

or

a = b - 2

Then if we select the first one, we get:

a + b = 12

(b + 2) + b = 12

2*b + 2 = 12

2*b = 12 -2 = 10

b = 10/2 = 5

b = 5

then a = b + 2= 5 + 2 = 7

The number is 75.

And if we selected:

a = b - 2, we would get the number 57.

Both are valid solutions because we are changing the order of the digits, so is the same:

75 + 57

than

57 + 75.

6 0
3 years ago
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