Answer:
it is located in quad III
Step-by-step explanation:
If there is a solution, y=y so we can say:
1.5x-1=1 add 1 to both sides
1.5x=2 divide both sides by 1.5
x=2/1.5
x=4/3 (exact)
x=1 1/3 (exact)
x≈1.33 (to nearest hundredth of a unit)
Answer:
d
Step-by-step explanation:
Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
Answer:
it would be $16 off 40 so the pants would be $24