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3 years ago

Help asap!!!! Answer soon

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

7 0

so they are like all in order and when your doing these if its like

5x5x5x5 would be 5^4 (< thats 5 with a tiny 4) and 5+5+5+5 is 5x4 so 1 one is the first box second is 2 and third is box 3 then the remaining are just none

and my bad again super sorry

Airida [17]3 years ago

5 0

Answer:

Step-by-step explanation:

the 8x8x8x8 goes to the 8^4

the 4+4+4+4+4+4+4+4 goes to the 4^8

the 8+8+8+8 goes to the 4x8

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Basile [38]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Determine whether 128 feet, 136 feet, and 245 feet can be the lengths of the sides of a triangle.

stich3 [128]

Yes they can because the two smaller numbers add up to be more than the bigger number

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4 years ago

I don't know how to do this please help

postnew [5]

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3 years ago

Is f(x)=-4x squared -2x-8, concave up or down

yKpoI14uk [10]

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3 years ago

write a variable expression to describe the rule of each progression then calculate the term 20 or 20 term1.) 6,12,18,24,...2.)3

Dmitriy789 [7]

1) 6, 12,18,24

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 6, d = 6

$\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 6 + 19}\times6 \\ T_{20\text{ }}\text{ = 6 + 114} \\ T_{20\text{ }}\text{ = 120} \end{gathered}$

2) 3,6,9,12

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 3, d = 3

$\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 3 + 19 }\times3 \\ T_{20\text{ }}\text{ = 3 + 57} \\ T_{20\text{ }}\text{ = 60} \end{gathered}$

3) 1,5,9,13

The rule used here is: Arithmetic Progression or Linear sequence

From the data above:

a = 1, d = 4

$\begin{gathered} T_{n\text{ }}=\text{ a + (n-1)d} \\ \text{where n = 20} \\ T_{20\text{ }}=\text{ a + (20-1)d} \\ T_{20\text{ }}\text{ = a + 19d} \\ T_{20\text{ }}\text{ = 1 + 19 }\times4 \\ T_{20\text{ }}\text{ = }1\text{ + 76} \\ T_{20\text{ }}\text{ = }77 \end{gathered}$

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1 year ago