Question

4. A study of air quality in a particular city by an environmental group suggest that t years from now the level of carbon monoxide, in parts per million , in the air will be A=0.2t^2+.01t+5.1.
4a. What is the current level of Carbon Monoxide, in part per million?
4b. How many years from now will the level of carbon monoxide be at 8 parts per million? Round to the nearest tenth.

Answer 1

Answer:

4A=5.1 per million 4B=3.8 years

Step-by-step explanation:

4A. A=0.2^2+.01t+5.1 the current level would be 5.1

4B. 8=.2t^2+.01+5.1 minus 8  .2t^2+.01-2.9

t=(-1.0+squ.0001-41-.58)/.4

t=(-.01+squ2.3201)/.4

t=3.78  t+3.78=0 =-3.78

t=-3.83 t-3.83=0 =3.83

Answer 3.83 years