The plane that is highlighted inside the given cuboid is called a Rectangle.
<h3>What is the Plane in the given solid?</h3>
A cross-section is the intersection of a solid and a plane. Plane Figures and defined as solid shapes.
In geometry, shapes are the forms of objects which have boundary lines, angles and surfaces. These figures demonstrate the shape of objects we see in our everyday lives. There are different types of 2D shapes and 3D shapes. The plane shapes are two-dimensional closed shapes with no thickness and are known as 2D shapes.
Solid shapes are nothing but solids with three dimensions: length, breadth, and height. Solid shapes are also known as 3D shapes.
Now, looking at the given figure we see that it is a cuboid and we see that the 2 dimensional plane cut through it is clearly a rectangle.
Thus, we can conclude that the plane that is highlighted inside the given cuboid is called a Rectangle.
Read more about Plane in Solid at; brainly.com/question/1609720
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A simple answer is that any given trapezoid with height h and length of the parallel lines a and b, is half of a parallelogram with an area of (a+b) x h. Since the trapezoid is half of this, it is h(a+b)/2
Answer:
f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)
Step-by-step explanation:
The answer would be false.
Answer:
y = -3/2 x + 4
Step-by-step explanation:
y-4 = -3/2 ( x-0)
y = -3/2 x + 4
