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Illusion [34]
3 years ago
11

The park is 3 miles long and 2 miles wide. manuel walked around the park two times. how many miles did he walk in all?

Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

Answer:

20 miles.

Step-by-step explanation:

You're on the right track with your answer of 12. You added the sides you knew & multiplied by 2.

I'm picturing the park like a rectangle. So there are two sides that are 3 miles long, and 2 sides that are 2 miles long. For perimeter, we add all the sides.

3 + 3 + 2 + 2 = 10. And he walked the park twice, so 2 x 10 = 20

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Answer:

a. The point estimate of the corresponding population mean is of $8213.

b. The margin of error is of $103.

c. The 98% confidence interval for the corresponding population mean is between $7973.5 and $8452.5, which means that for all weedings, we are 98% sure that the true population mean is in this interval.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. What is the point estimate of the corresponding population mean?

The sample mean is of $8213. So, by the Central Limit Theorem, the point estimate of the corresponding population mean is of $8213.

b. What is the margin of error for this estimate (use2 standard deviations (divided by Vn) to either side of the mean is used when no specific confidence level is stated).

Sample of 450, standard deviation of $2185. So

M = \frac{2185}{\sqrt{450}} = 103

The margin of error is of $103.

c. Create and interpret a 98% confidence interval for the corresponding population mean.

The confidence interval is given by:

\mu \pm M*z

In which \mu is the sample mean and z is the value related to the confidence level.

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.325.

Then

\mu - M*z = 8213 - 2.325*103 = 7973.5

\mu + M*z = 8213 + 2.325*103 = 8452.5

The 98% confidence interval for the corresponding population mean is between $7973.5 and $8452.5, which means that for all weedings, we are 98% sure that the true population mean is in this interval.

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